Investigate how the Concentration of a Sucrose Solution affects the Rat

Investigate how the Concentration of a Sucrose Solution affects the Rate of OsmosisIntroductionDiffusion is the movement of particles from a high meanness to alow concentration until they are spread out evenly. An example of diffusion is when an aerosol is sprayed. The particles spread out fromthe high concentration at the nozzle into the roost of the room andthat is how the smell moves.Osmosis is the passage of water molecules from a weaker solution to astronger solution through a parti eachy permeable membrane. Osmosis is atype of diffusion involving water - the water molecules move from aweak solution (with a high concentration of water) into a strongsolution (with a low concentration of water).The cell membrane in a plant cell is partially permeable - it hassmall holes that can let in small molecules but non large ones. Thisallows water through and therefore allows osmosis.When the cell has all the water it can take inside of it the osmosisprocess stops. The water pushes up ag ainst the cell hem in which isstrong overflowing to stop it bursting. The cell is turgid and the plantneeds turgid cells to arrest it rigidity and allow it to stand upright.If the cell has not enough water in it, it is flaccid and doesntsupport the plant which goes limp.In order to prepare for my taste I did a preliminary experimentto get an topic of how I would do my real experiment and what apparatusand solutions I would need. I weighed 11 potato chips and put theminto separate boiling tubes. I filled individually boiling tube with adifferent concentration of a sucrose solution from 0 molars (water)through to 1.0 molar with 0.1M intervals in amid. After 30 minutesI removed the potato chips and measured their bundle. I found that thechips in the concentrations of 0M to 0.2M had augmentd in mass andthe rest had decreased in mass. For my experiment I have chosen to use quint concentrations of sucrose solution - 0.0M, 0.1M, 0.2M, 0.3M and0.4M. I have chosen these concentrati ons for two reasons. Firstly theycover the point at which the increase in mass changes to a decreaseand therefore I can hopefully find the equilibrium where the massstays the same, and secondly they are all at equal intervals so itwill be easy and accurate to draw a graph for my results.PredictionI predict that out of the five potato chips used in the experiment atleast two will... ...tato chipin the solution for different time periods. I could then equivalence thegradients of the lines of best fit for the 5 different times, and alsodraw graphs for each molarity across the 5 time periods. I could alsodo an experiment using the same concentrations as I did in thisexperiment, but measuring the mass of the potato chips after every 3or 4 hours until the mass stays the same, and see how long potatochips in different solutions took to reach a final mass and to see howlarge its mass would get. Finally I would like to do the sameexperiment as I did here, but try it out on different types of plantsand compare the rates of osmosis of the different plants. This wouldgive an idea of which plants were more efficient at taking up waterand I could see what types of plants had the fastest rate of osmosis,and whether there was a link between the rate of osmosis in a plantand the habitat it exists in. For example I might find that plantsthat live in hot, dry conditions have a blistering rate of osmosis thanplants which live in cold, wet environments. These experiments wouldhelp give a better idea of how the rate of osmosis is affected by theconcentration of a solution.